((x^2-x-1)/(3x-5))-1=0

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Solution for ((x^2-x-1)/(3x-5))-1=0 equation: 


D( x )

3*x-5 = 0

3*x-5 = 0

3*x-5 = 0

3*x-5 = 0 // + 5

3*x = 5 // : 3

x = 5/3

x in (-oo:5/3) U (5/3:+oo)

(x^2-x-1)/(3*x-5)-1 = 0

(x^2-x-1)/(3*x-5)+(-1*(3*x-5))/(3*x-5) = 0

x^2-1*(3*x-5)-x-1 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

(x-2)^2 = 0

((x-2)^2)/(3*x-5) = 0

((x-2)^2)/(3*x-5) = 0 // * 3*x-5

(x-2)^2 = 0

x-2 = 0 // + 2

x = 2

x in { 2, 2 }

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